WebOct 7, 2013 · Task tr = Task.WhenAll (new Task [] { t0, t1, t2, t3, t4 }); Task.WaitAny (tcs.Task, tr); if (tcs.Task.IsCompleted) return tcs.Task.Result; return false; This also fixes a race condition in your code: tr.IsCompleted could be true, even if some task returned true, because all of the tasks could finish at the same time. WebNov 10, 2014 · If the tasks you're awaiting have a result of the same type Task.WhenAll returns an array of them. For example for this class: public class Test { public async Task TestAsync () { await Task.Delay (1000); // Imagine an I/O operation. return new TestResult (); } } We get these results:
c# - To use Task.WhenAll, or not to use Task.WhenAll - Stack Overflow
WebInstead of iterating over all tasks, you can get the Exceptions (if any) from the Task.WhenAll -Task: var taskResult = Task.WhenAll (tasks); try { await taskResult; } catch (Exception e) { if (taskResult.IsCanceled) { // Cancellation is most likely due to a shared cancellation token. WebC# Task.WhenAll用于ValueTask,c#,task-parallel-library,valuetask,C#,Task Parallel Library,Valuetask,是否存在任务的等价物。当所有接受任务时ValueTask 我可以使用 Task.WhenAll(tasks.Select(t => t.AsTask())) 如果他们都在包装一个任务,这将很好,但它会强制将任务对象无效地分配给realValueTask,根据设计,否: 方法可能会返回此值 ... rhymes with lipid
What is the difference between Task.WhenAll () and Task.WaitAll () in C#?
WebJun 27, 2024 · Tasks property returns all tasks from the entire linked list. ResultSync() recursively applies mapper functions to the task results (all the tasks are supposed to be already resolved). Result() resolves all tasks (through await Task.WhenAll(Tasks)) and returns result of ResultSync() WebHowever, the order in which the tasks are executed may be different. In general, you should use multiple await statements when you need to execute tasks in a specific order, and use Task.WaitAll or Task.WhenAll when you need to wait for multiple tasks to complete in parallel. More C# Questions. Tuple vs string as a Dictionary key in C# WebJun 18, 2024 · 0. You can try this. Task.Factory.StartNew ( () => taskList.ForEach (task => task.Start ())); or you can try. Parallel.ForEach (taskList, task => task.Start ()); That … rhymes with lively